Posted by Sarah on Tuesday, February 10, 2009 at 10:29pm.
I would find the voltage on the capacitor, or Electric field first. Using Gauss Law, then E= sigma/2epsilion
Force/q= E
Force=Eq
force*distance=Eq*distance
1/2 m v^2=Eq*distance
solve for velocity v.
The E field between the plates is proportional to the charge per unit area, sigma (1.5 x 10-7 C/m2).
E = sigma/epsilon
where epsilon is the permittivity of free space, which you should look up.
The kinetic energy that is given to the electrion while crossing the gap of length X is
KE = e E X
Set that equal to the final kinetic energy and solve for the velocity.
Dr WLS is correct, E between the plates is sigma/episilon, not sigma/2epsilon.
Related Questions
Physics - An electron is released from rest at the negative plate of a parallel ...
Physics #48 - An electron is released from rest at the negative plate of a ...
physics - An electron is released from rest at the negative plate of a parallel ...
Physics - An electron is released from rest at the negative plate of a parallel ...
physics - An electron is released from rest at the negative plate of a parallel ...
physics - The plates of a parallel plate capacitor are separated by a distance ...
College physics - Two 2.4 cm diameter disks spaced 1.5 mm apart form a parallel-...
College Physics - A parallel plate capacitor is made of two 3.5 cm x 3.5 cm ...
physics - An electron is released at the negative plate of a parallel plate ...
Science - Use the following values for mass and charge: an electron has mass me...
For Further Reading
