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March 3, 2015

Posted by **beeca** on Tuesday, February 10, 2009 at 9:50pm.

- MATH!! -
**beeca**, Tuesday, February 10, 2009 at 10:14pmplz help TIRREEEDDD NEED ASSISTANCE. sorry im a little pushy but NEED HELP!!

- MATH!! -
**beeca**, Tuesday, February 10, 2009 at 10:26pm... plz???

- MATH!! -
**beeca**, Tuesday, February 10, 2009 at 10:48pmalright thats fine jus thelp everyone else out first. dont help me. :(

- MATH!! -
**drwls**, Wednesday, February 11, 2009 at 8:58amHer total time for 6 races must be under

6 x (5 5/6 min) = 35 min

Total time for the first five races is already ---. (Add them up). You seem to have made a mistake and listed six times, with 5 min 53 s appearing twice. Subtract the sum of her FIVE times from 35 minutes to find out how fast she must run the sizth race.

If the 5min 53 s time as supposed to appear only once, her total times so far add up to 27 min 134 s = 29 min 14 s. The last race must be run in under 5 min 46 s. That should be possible, since she has run that fast before.

- MATH!! -
**baaab :)**, Thursday, November 25, 2010 at 5:15pmheehee

- MATH!! -
**baaab :)**, Thursday, November 25, 2010 at 5:24pmthanks for the help...

really didnt need to do anything to figure this out...

:D

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