a 2390 kg car traveling to the west at 22.4 m/s slows down uniformly under a force of 8740 N to the east.
(a) How much force would be required to cause the same acceleration on a car of mass 3140 kg? Answer in units N
(b) How far would the car move before stopping? Answer in units of m.
physics - drwls, Tuesday, February 10, 2009 at 12:09am
(a) If the two cars have the same deceleration rate, the applied force must be proportional to the mass. The speed does not matter for this part.
(b) The deceleration rate is a = F/m = 3.66 m/s^2
The average speed while decelerating is Vav = 22.4 m/s/2 = 11.2 m/s
The time spent decelerating is T = Vo/a = 6.12 seconds
Distance travelled = Vav*T = ?