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January 27, 2015

January 27, 2015

Posted by **Alyn** on Monday, February 9, 2009 at 9:12pm.

I tried to factor 2x^2+4x+1 but ended up with something that didn't work. Am I missing something here? I'm so lost.

Thanks in advance,

Alyn

- calculus - functions! -
**Reiny**, Monday, February 9, 2009 at 9:33pmsince the resulting h(x) is quadratic, g(x) must have been quadratic

let g(x) = ax^2 + bx + c

then

f(g(x)) = 2(ax^2 + bx + c) + 1

= 2ax^2 + 2bx + 2c+1

but this is equal to 2x^2 + 4x + 1

so 2a = 2 , a = 1

2b = 4, b = 2

2c+1 = 1, c = 0

so g(x) = x^2 + 2x

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