Sunday
March 29, 2015

Homework Help: chemistry...Please Help

Posted by Saira on Monday, February 9, 2009 at 6:39pm.

I posted this below and received help but im still lost and worked out the problem but am getting the wring answer:

--------------------
Given the equilibrium constant values:

1.N2(g)+ 1/2O2(g)<---> N2O(g)
KC=2.7*10^{-18}

2.N2O4(g)<----> 2NO2(g)
KC= 4.6*10^{-3}

3. 1/2N2(g)+ O2(g)<----> NO2(g)
KC=4.1*10^{-9}

-----------------------------
2N2O(g)+ 3O2 (g) <----> 2N2O4(g)


I need help i dunt know what to do next Part:



1.2N2(g)+ O2(g)<---> 2N2O(g) (*2)
KC=5.4*10^{-18}

2.2NO2<----> N2O4(g)
KC= 1/4.6*10^{-3}


I know i flip the second equation so Kc is flipped over 1...and i multiplied the 1st equation by 2:

Now i don't know what to do i don't know how they got to the final equation.




Responses

* Chemistry....Please help - DrBob222, Sunday, February 8, 2009 at 7:24pm

Reverse 1.
Multiply 3 by 2.
Reverse 2.
Add the equations and you get 1/2 of the equation you want (if I didn't goof), then double that (and square the resulting K).

-----------------------------------


Okay so this is what i did:



1.FLIP= N2O <--> N2 + 1/2O2
Kc= 1/2.7*10^{-18}= 3.7*10^17

2. FLIP= 2NO2 <---> 2NO2O4
Kc= 1/4.6*10^{-3}= 217.39

3. MULTIPLY BY 2
N2 + 2O2 <---> 2NO2
Kc= 4.1*10^{-9} * 2= 8*10^-9

---------------------------------

THE FINAL EQUATION SHOULD BE :

2N2O(g)+ 3O2 (g) <----> 2N2O4(g)

AND I'M NOT GETTING IT RIGHT AND I DON'T UNDERSTAND WHAT GETS CANCELED OUT I'M CONFUSED AND THE FINAL Kc I KEEP GETTING IS WRONG...

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