Posted by **Saira** on Monday, February 9, 2009 at 6:39pm.

I posted this below and received help but im still lost and worked out the problem but am getting the wring answer:

--------------------

Given the equilibrium constant values:

1.N2(g)+ 1/2O2(g)<---> N2O(g)

KC=2.7*10^{-18}

2.N2O4(g)<----> 2NO2(g)

KC= 4.6*10^{-3}

3. 1/2N2(g)+ O2(g)<----> NO2(g)

KC=4.1*10^{-9}

-----------------------------

2N2O(g)+ 3O2 (g) <----> 2N2O4(g)

I need help i dunt know what to do next Part:

1.2N2(g)+ O2(g)<---> 2N2O(g) (*2)

KC=5.4*10^{-18}

2.2NO2<----> N2O4(g)

KC= 1/4.6*10^{-3}

I know i flip the second equation so Kc is flipped over 1...and i multiplied the 1st equation by 2:

Now i don't know what to do i don't know how they got to the final equation.

Responses

* Chemistry....Please help - DrBob222, Sunday, February 8, 2009 at 7:24pm

Reverse 1.

Multiply 3 by 2.

Reverse 2.

Add the equations and you get 1/2 of the equation you want (if I didn't goof), then double that (and square the resulting K).

-----------------------------------

Okay so this is what i did:

1.FLIP= N2O <--> N2 + 1/2O2

Kc= 1/2.7*10^{-18}= 3.7*10^17

2. FLIP= 2NO2 <---> 2NO2O4

Kc= 1/4.6*10^{-3}= 217.39

3. MULTIPLY BY 2

N2 + 2O2 <---> 2NO2

Kc= 4.1*10^{-9} * 2= 8*10^-9

---------------------------------

THE FINAL EQUATION SHOULD BE :

2N2O(g)+ 3O2 (g) <----> 2N2O4(g)

AND I'M NOT GETTING IT RIGHT AND I DON'T UNDERSTAND WHAT GETS CANCELED OUT I'M CONFUSED AND THE FINAL Kc I KEEP GETTING IS WRONG...

- chemistry...Please Help -
**GK**, Monday, February 9, 2009 at 8:18pm
Here is my take on the question without any guarantees:

1. Reverse and multiply by 2

N2(g)+ 1/2O2(g)<---> N2O(g) Kc=2.7*10^-18

2N2O –> 2N2 + O2 K1 = [1 / 2.7*10^-18]^2

2. Reverse and multiply by 2

N2O4(g)<----> 2NO2(g) Kc= 4.6*10^-3

4NO2 –> 2N2O4 K2 = [1 / 4.6*10^-3]^2

3. Multiply by 4

1/2N2(g)+ O2(g)<----> NO2(g) Kc=4.1*10^-9

2N2+ 4O2<----> 4NO2 K3 = [4.1*10^-9 ]^4

Adding left sides and right sides, and doing cancellations, we get:

2N2O(g)+ 3O2 (g) <----> 2N2O4(g) K = (K1)(K2)(K3)

- chemistry...Please Help -
**DrBob222**, Monday, February 9, 2009 at 9:02pm
When I worked the problem for you a couple days ago, I arrived at an equation with 1/2 the coefficients but I squared the final K which would have been correct. However, I DID NOT square the reverse of 2 after I multiplied the equation by 2. GK is correct and I goofed. The rest of my answer procedure correct.

- chemistry...Please Help -
**Saira**, Monday, February 9, 2009 at 9:13pm
Thank YOu both of you i got the answer

## Answer this Question

## Related Questions

- chemistry - Given the equilibrium constant values: N2 + 1/2O2 >>> N2O...
- Chemistry....Please help - Given the equilibrium constant values: 1.N2(g)+ 1/2O2...
- CHEMISTRY - A chemist studying the equilibrium N2O4(g)<----->2NO2(g) ...
- chemistry - On this problem I keep getting the wrong answer. I am subtracting ...
- Chemistry - Please show step by step with answer The equilibrium constant, Kc, ...
- chemistry - i already posted this question, but im still confused on it. ...
- chemistry - Given Kc values: N2(g)+1/2 O2(g)<->N2O(g) Kc=2.7* 10^-18 N2O4(...
- CHEMISTRY HELP STILL NEEDED PLEASE!!! - Given: N2O4 (g) « 2NO2 (g) @ 25 degrees ...
- chemistry - Can you please check if I came up with the right answer for this ...
- Chemistry - SO this is my first time doing this... lol i need help on an AP ...