Posted by Juliet on Monday, February 9, 2009 at 4:41pm.
Given Kc values:
N2(g)+1/2 O2(g)<->N2O(g) Kc=2.7* 10^-18
What is the Kc value for:
- chemistry - drwls, Monday, February 9, 2009 at 6:28pm
[NO2]^2/[N2O4] = 4.6*10^-3
[N2O4]/[NO2]^2 = 217.4
[N2O4]^2 = 4.73*10^4 [NO2]^4
= 4.73*10^4 *[N2]^2[O2]^4
Now use the fact that
[N2O]^2 = [N2]^2*[O2]*7.29*10^-36
[N2]^2*[O2] = 1.37*10^35 [N2O]^2
[N2O4]^2 = 4.73*10^4*1.37*10^35 [N2O]^2*[O2]^3
= 6.49*10^39 [N2O]^2*[O2]^3
Kc = 6.49*10^39
check my math
- chemistry - Juliet, Monday, February 9, 2009 at 7:46pm
The answer is wrong.
Kc (Equilibrium Constant) is always <1.
- chemistry - drwls, Tuesday, February 10, 2009 at 12:53am
The answer may be wrong due to a math error I might have made, but Kc can certainly be greater than 1.
This is essentially an algebra problem. Using the concentration ratios you have been given, calculate the Kc for the indicated reaction.
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