No. Your first step is IK but unecessary, and your second differentiation step is wrong.
Differentiate both sides of the equation with repect to x, remembering that y is a function of x. Use the "chain rule" when necessary.
cos(2x+3y)*(2 + 3dy/dx) = 6y^2x^2 +6x^3*y*dy/dx
Rearrange and solve for dy/dx
= -2cos(2x+3y)- 6y^2x^2
One more step
Thanks for your reply.
I tried again and got
cos(2x+3y)*(2 + 3dy/dx = 9x^2y^2 + (6x^3*y dy/dx)
Looking at your answer it seems wrong also.
Should it not be 9y^2x^2... on the 1st part of the right hand side of your equation? Or am I missing something here?
Getting stuck on the rearranging but will it another try
Yes, it's 9x^2 y^2 where I had a coefficient of 6. Good work!
Awesome. Think I've done it!
Cheers for the help.
Answer this Question
Calculus - Use implicit differentiation to find dy/dx. e^4x = sin(x+2y). This is...
Calculus - Find dy/dx of 3 sin x cos y = 2 using implicit differentiation.
Calculus - Find dy/dx using implicit differentiation of xy + sin^2y=10350. Is it...
Ap Calc AB - Determine (dy/dx) using implicit differentiation. cos(X^2Y^2) = x I...
Calculus I - Find the derivative of f(x) = sin^2 (e^sin^2 x) I wonder if I'm ...
Calculus - Find dy/dx for y=sin(x+y) A. 0 B. (cos(x+y))/(1-cos(x+y) C. cos(x+y) ...
calculus - find y' by implicit differentiation: 5cos(x)*sin(y)=13
calculus - Find dy/dx by implicit differentiation. sin x = x (1 + tan y)
Calculus - How do you use imlicit differentiation to differentiate e^(xy)? I ...
calculus - Using 4x^2 - 9y^2 = 36 Find y by implicit differentiation and then ...