Posted by Sabrina on Sunday, February 8, 2009 at 9:22pm.
Prob(rain 1stday)*prob(rain 2nd day)*prob(rain 3rd day)
= (.6)(.6)(.6) = .216
I do not believe you can apply statistics to weather in the manner described... Especially in Seattle, where rainy periods come in long cycles that are often incorrectly predicted. (I am from Seattle, and spend a month or two there every year). The weather you get one day is strongly correlated with that of previous days.
Reiny has given you the answer they are probably looking for, but I believe a more realistic value is more like 35%.
They picked a poor example for teaching purposes.
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