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October 20, 2014

October 20, 2014

Posted by **Candace** on Sunday, February 8, 2009 at 4:35pm.

A ground state H atom absorbs a photon of wavelength 94.91 nm, and its electron attains a higher energy level. The atom then emits two photons: one of wavelength 1281 nm to reach an intermediate level, and a second to reach the ground state.

a) What higher level (n=?) did the electron reach?

b) What intermediate level (n=?) did the electron reach?

c) What was the wavelength of the second photon emitted?

Thanks

- chemistry -
**DrBob222**, Sunday, February 8, 2009 at 8:52pmFor #a.

delta E1 = hc/wavelength but change 94.91 nm to meters first. Then use

delta E1 = 2.180 x 10^-18*[(1/n_{1}^{2})-(1/n_{2}^{2})] where n_{1 = 1 (the first shell of hydrogen; i.e., the ground state). Solve for N2. I obtained 5 for n2. (That isn't n^2; that is n^2 = 25 + change but round to 25.). part b. Go through the same procedure for the 1281 nm line and determine n1. N1 is the final state and n=5 (that's n from part A). Solve for n1. I obtained 3 for that. That leaves part c to do. The difference in energy must be the amount from n=1 to n=5 minus the energy from n=5 to n=3. The easiest way to do that is to use the above formula and plub in n1 = 1 and n2 = 3. Show your work if you get stuck. }

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