Posted by Candace on Sunday, February 8, 2009 at 4:35pm.
For #a.
delta E1 = hc/wavelength but change 94.91 nm to meters first. Then use
delta E1 = 2.180 x 10^-18*[(1/n12)-(1/n22)] where n1 = 1 (the first shell of hydrogen; i.e., the ground state). Solve for N2. I obtained 5 for n2. (That isn't n^2; that is n^2 = 25 + change but round to 25.).
part b.
Go through the same procedure for the 1281 nm line and determine n1. N1 is the final state and n=5 (that's n from part A). Solve for n1. I obtained 3 for that.
That leaves part c to do. The difference in energy must be the amount from n=1 to n=5 minus the energy from n=5 to n=3. The easiest way to do that is to use the above formula and plub in n1 = 1 and n2 = 3.
Show your work if you get stuck.
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