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chem

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You're asked to prepare 125mL of .0321 M AgNO3. How many grams would you need of a smaple known to be 99.81% AgNO3 by mass?

  • chem - ,

    masspureAgNO3=molmassAgNO3*volumeinLiter*molarity

    MassAgNO3= massabove/.9981

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