posted by Katherine .
So here's the problem:
6a^-2 + 9a^2 all over 3a^-2
The answer is suppose to be 2 + 3a^4
I keep getting the answer as 5.
Can you show me how to solve this problem correctly?
how about multiplying top and bottom of your fraction by a^2 to get
(6 + 9a^4)/3
= 2 + 3a^4