the length of a rectangle is twice the width. The area is 200 yd^2 Find the length and the width.

The length is _____ yd
The width is ______ yd

Could I get help please!!!!

If you say the length is 2x and the width is x, you get

(2x)(x)=200
so x=10
length is 2x so = 20 yd
width is x = 10 yd

Well, let's solve this riddle together, shall we? We have a rectangle with length and width, and we know that the length is twice the width. We also know that the area of the rectangle is 200 yd^2.

So, let's call the width of the rectangle W. Since the length is twice the width, we can call the length L = 2W.

Now, we can use the formula for the area of a rectangle, which is Length x Width. In this case, the area is 200 yd^2, so we can write the equation as:

L x W = 200

Substituting in our values for L and W, we get:

2W x W = 200

Simplifying, we have:

2W^2 = 200

Dividing both sides by 2, we get:

W^2 = 100

Taking the square root of both sides, we find:

W = 10

So, the width of the rectangle is 10 yd. Since the length is twice the width, the length is:

L = 2W = 2(10) = 20 yd

Therefore, the length of the rectangle is 20 yd and the width is 10 yd.

Sure! Let's solve the problem step by step.

Step 1: Let's assign variables to the length and width of the rectangle.
Let's say the width of the rectangle is "w" yards.

Step 2: According to the problem statement, the length of the rectangle is twice the width. So, we can represent the length as "2w" yards.

Step 3: The area of a rectangle is given by the formula: Area = length × width.
In this case, the area is given as 200 yd^2. So, we can write the equation as:
200 = 2w × w

Step 4: Simplify the equation and solve for the width.
Multiply 2w by w:
200 = 2w^2

Step 5: Rearrange the equation to isolate w^2:
2w^2 = 200

Step 6: Divide both sides of the equation by 2 to solve for w^2:
w^2 = 100

Step 7: Take the square root of both sides to find the value of w:
w = √100
w = 10

So, the width of the rectangle is 10 yards.

Step 8: Now we can find the length by substituting the value of the width (w) into the expression for the length (2w):
Length = 2w = 2(10) = 20

Hence, the length of the rectangle is 20 yards.

To summarize:
The length is 20 yd
The width is 10 yd

Of course! I'd be happy to help you with this problem.

Let's start by assigning variables to the length and width of the rectangle. Let's say the width is represented by 'w' yards. Since the length is twice the width, we can represent the length as '2w' yards.

The formula for the area of a rectangle is length multiplied by width. In this case, the area is given as 200 square yards. So we can set up the equation:

Area = Length * Width
200 = (2w) * w

Now we can solve this equation to find the width.

200 = 2w^2 (simplifying by multiplying 2w by w)
100 = w^2 (dividing both sides by 2w)

Taking the square root of both sides, we get:
w = √100

The square root of 100 is 10. However, since we are dealing with a physical length, the width cannot be negative, so we take only the positive square root. Therefore, the width is 10 yards.

Now that we have the width, we can find the length by using the relationship stated in the problem. Since the length is twice the width, we have:
Length = 2w = 2 * 10 = 20 yards.

So, the length of the rectangle is 20 yards, and the width is 10 yards.