I just want to make sure that I have this right.
If 2.4 m^3 of a gas initially at STP is compressed to 1.6 m^3 and its temperature raised to 30 degrees C, what is the final pressure?
P2 = T2p1v1 / V2t1
P2 = (303.15*1*2.4) / (1.6 *273.15)
P2 = 727.56 / 437.04
P2 = 1.66 atm
Is this correct?
Looks good to me.
Thanks
To determine if the calculation is correct, let's go step by step and compare it with the correct process.
First, let's understand the equation used to solve for the final pressure, P2:
P2 = (T2 * P1 * V1) / (V2 * T1)
Where:
- P2 = final pressure
- T2 = final temperature in Kelvin
- P1 = initial pressure at STP (Standard Temperature and Pressure), which is 1 atm
- V1 = initial volume at STP
- V2 = final volume after compression
- T1 = initial temperature in Kelvin
Given information:
- P1 = 1 atm
- T2 = 30 degrees Celsius = 30 + 273.15 = 303.15 K
- V1 = 2.4 m^3
- V2 = 1.6 m^3
- T1 = 273.15 K (since it is at STP)
Now let's substitute the values into the equation:
P2 = (303.15 * 1 * 2.4) / (1.6 * 273.15)
P2 = 727.56 / 437.04
P2 = 1.664 atm (rounded to three decimal places)
Therefore, based on the calculation, the correct value for the final pressure is approximately 1.664 atm, which matches your answer.
So, yes, your calculation is correct!