Thursday

August 21, 2014

August 21, 2014

Posted by **chemstudent** on Friday, February 6, 2009 at 10:31am.

Find the temperature

pV=nRT

T = p*V/(n*R)

T = 1 atm * 0.5 liters / (2 moles * .08206 L atm K^-1 * mol^-1)

T = 3.04 K

Did I do that problem correctly? That temperature seems unrealistically low.

- Chemistry -
**DrBob222**, Friday, February 6, 2009 at 11:45amYes, that's correct. Note that

T = p*v/(n*R)

so T = 273 K when p is 1 atm, v is 22.4 L, and n = 1. So you have reduced v from 22.4 to 0.5 AND you have reduced the number even more by doubling the denominator.

**Related Questions**

calculus help thanks! - The gas law for an ideal gas at absolute temperature T (...

college (physics thermo) - A 1.20 mol sample of an ideal diatomic gas at a ...

chemistry - 17 liters of a gas is at an initial temperature of 67 degrees C and ...

Chemistry - A sample of air was compressed to a volume of 18.0 L. The ...

Chemistry - I have a balloon that contains 22 grams of Carbon dioxide. The ...

Chemistry - If 5.01 moles of an ideal gas has a pressure of 4.81 atm, and a ...

chemistry - sample of argon gas collected at a pressure of 1.11 atm and a ...

chemistry - A sample of an ideal gas at 1.00 atm and a volume of 1.61 L was ...

physics - A 1.80 mol sample of an ideal diatomic gas at a pressure of 1.20 atm ...

chemistry - A sample of gas with a volume of 2.0 L exerts a pressure of 1.0 atm...