Posted by **chemstudent** on Friday, February 6, 2009 at 10:31am.

A sample of an ideal gas consists of 2 moles, pressure = 1 atm, volume = 0.5 liters

Find the temperature

pV=nRT

T = p*V/(n*R)

T = 1 atm * 0.5 liters / (2 moles * .08206 L atm K^-1 * mol^-1)

T = 3.04 K

Did I do that problem correctly? That temperature seems unrealistically low.

- Chemistry -
**DrBob222**, Friday, February 6, 2009 at 11:45am
Yes, that's correct. Note that

T = p*v/(n*R)

so T = 273 K when p is 1 atm, v is 22.4 L, and n = 1. So you have reduced v from 22.4 to 0.5 AND you have reduced the number even more by doubling the denominator.

## Answer this Question

## Related Questions

- chemistry - If I contain 3 moles of gas in a container with a volume of 60 ...
- chemistry - 17 liters of a gas is at an initial temperature of 67 degrees C and ...
- calculus help thanks! - The gas law for an ideal gas at absolute temperature T (...
- chemistry - Ideal Mixed Gas Law problems 1. What is the pressure generated by a ...
- Chemistry - A sample of air was compressed to a volume of 18.0 L. The ...
- Chemistry - I have a balloon that contains 22 grams of Carbon dioxide. The ...
- Chemistry - A sample of gas with a volume of 14.9 liters at 2.6 atmospheres ...
- chemistry - sample of argon gas collected at a pressure of 1.11 atm and a ...
- college (physics thermo) - A 1.20 mol sample of an ideal diatomic gas at a ...
- Chemistry - Calculate the volume occupied by 200g of steam at 200 °C and 0.5 atm...

More Related Questions