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April 24, 2014

April 24, 2014

Posted by **Angela** on Thursday, February 5, 2009 at 10:23pm.

a. that all will be underweight

b.none will be underweight

c. at least one will be underweight

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**bobpursley**, Thursday, February 5, 2009 at 10:45pmpr(a.)=18/100*18/100*18/100*18/100

I will be happy to check the others. On the last, remember there are four ways the combination can occur

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**bobpursley**, Thursday, February 5, 2009 at 10:48pmSorry, on the last, you could have

4 ways to have one underweight

UFFF, FUFF, FFUF, FFFU

Ways to have two U

UUff, UfUf, UffU, FUUf, FUfU, FfUU

Ways to have three U

UUUf, UfUU, FUUU, UUfU

Ways to have four U.

UUUU

- pre statistics -

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