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pre statistics

posted by on .

In a recent health study it was claimed that 18% of americans are underwieght.If 4 americans randomly selected what is the probability that

a. that all will be underweight
b.none will be underweight
c. at least one will be underweight

  • pre statistics - ,

    pr(a.)=18/100*18/100*18/100*18/100

    I will be happy to check the others. On the last, remember there are four ways the combination can occur

  • pre statistics - ,

    Sorry, on the last, you could have

    4 ways to have one underweight
    UFFF, FUFF, FFUF, FFFU
    Ways to have two U
    UUff, UfUf, UffU, FUUf, FUfU, FfUU
    Ways to have three U
    UUUf, UfUU, FUUU, UUfU
    Ways to have four U.
    UUUU

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