# Chemistry

posted by
**Saira**
.

A mixture initially contains A,B, and C in the following concentrations: A1 = 0.300 M, B1 = 1.15M, and C1 = 0.350 M. The following reaction occurs and equilibrium is established:

A+2B <---> C

At equilibrium, A2 = 0.190M and C2 = 0.460M.

Calculate the value of the equilibrium constant, Kc

I am not sure what to do:

This is what i did but i think its wrong:

SO since,

Kc= (C)^C/(A)^a*(B)^b

(0.350)/(0.300)(1.15)=(0.460/(0.190)(B)^2

=(0.350)/(0.345)/(0.460/(0.190)(B)^2

What i did is square root both sides to get rid of B2,then i solve for b i got 1.53.

Then i sub that in the equation:

Kc= 0.460/ (0.190)(1.53)

BUt the answer is wrong