Algebra
posted by Amy .
I need help refreshing my memory. How can you tell if a problem like this has a solution or not?
4x^2
I forgot how you can tell please refresh my memory. Thank you! :)

As far as I know, there isn't a solution because the ^2 is to the x, not the 4, and since you obviously don't know what x is (unless you do then there is a solution), it just stays like that. I hope I helped!

It can be factored into (2x)(2x), if that is what you were asked to do. However, from the way you have it stated, I'm not sure what you are asking. In the future, please be more specific in stating your problem. Thanks.
I hope this helps.