Here is what I got to do : write an inequality for my classmates to solve. In my inequality, use both the multiplication and addition properties of inequalities; before I summit this to class I want to know if I did it right: 5(x + 8) -6 > 4(x + 6);

5x + 40 - 6 > 4x + 24; 5x + 44 - 44 > 4x + 24 - 44; 5x - 4x > 4x - 4x -20; 1x/1 < -20/1; x<-20, is this right?

Responses

Algebra - bobpursley, Thursday, February 5, 2009 at 11:35am
5(x + 8) -6 > 4(x + 6);
5x + 40 - 6 > 4x + 24;
5x + 44 - 44 > 4x + 24 - 44;
5x - 4x > 4x - 4x -20;

1x/1 < -20/1; Where in the world did you get this step? You did not divide by a negative.

Algebra - A. W., Thursday, February 5, 2009 at 11:41am
I got 5x-4x> 4x - 4x-20; 1x< -20; you have to get x by itself so you divide both side by 1; 1x/1 < -20/1; x< -20 that is how I got x<-20

You are almost correct in your answer, but there is a mistake in your explanation.

Let's go through the steps of solving the inequality correctly:

1. Start with the given inequality: 5(x + 8) - 6 > 4(x + 6)
2. Distribute the multiplication: 5x + 40 - 6 > 4x + 24
3. Combine like terms: 5x + 34 > 4x + 24
4. Subtract 4x from both sides: 5x - 4x + 34 > 4x - 4x + 24
This simplifies to: x + 34 > 24
5. Subtract 34 from both sides: x + 34 - 34 > 24 - 34
This simplifies to: x > -10

So, the correct inequality is x > -10, not x < -20.

To explain why your explanation is incorrect, you said that you have to divide both sides by 1. However, dividing by 1 does not change the inequality. Dividing both sides by 1 would simply give you x > -20, which is not the correct answer.

The correct answer is x > -10, which means that any value greater than -10 would satisfy the inequality.