Algebra
posted by A. W. on .
Here is what I got to do : write an inequality for my classmates to solve. In my inequality, use both the multiplication and addition properties of inequalities; before I summit this to class I want to know if I did it right: 5(x + 8) 6 > 4(x + 6);
5x + 40  6 > 4x + 24; 5x + 44  44 > 4x + 24  44; 5x  4x > 4x  4x 20; 1x/1 < 20/1; x<20, is this right?

5(x + 8) 6 > 4(x + 6);
5x + 40  6 > 4x + 24;
5x + 44  44 > 4x + 24  44;
5x  4x > 4x  4x 20;
1x/1 < 20/1; Where in the world did you get this step? You did not divide by a negative. 
I got 5x4x> 4x  4x20; 1x< 20; you have to get x by itself so you divide both side by 1; 1x/1 < 20/1; x< 20 that is how I got x<20

I agree with your 5x4x> 4x  4x20;
that simplifies to x>20
From there, your work makes no sense, and is in fact wrong. Dividing by 1 does not reverse the inequality sign