Posted by **A. W.** on Thursday, February 5, 2009 at 11:28am.

Here is what I got to do : write an inequality for my classmates to solve. In my inequality, use both the multiplication and addition properties of inequalities; before I summit this to class I want to know if I did it right: 5(x + 8) -6 > 4(x + 6);

5x + 40 - 6 > 4x + 24; 5x + 44 - 44 > 4x + 24 - 44; 5x - 4x > 4x - 4x -20; 1x/1 < -20/1; x<-20, is this right?

- Algebra -
**bobpursley**, Thursday, February 5, 2009 at 11:35am
5(x + 8) -6 > 4(x + 6);

5x + 40 - 6 > 4x + 24;

5x + 44 - 44 > 4x + 24 - 44;

5x - 4x > 4x - 4x -20;

1x/1 < -20/1; **Where in the world did you get this step? You did not divide by a negative.**

- Algebra -
**A. W.**, Thursday, February 5, 2009 at 11:41am
I got 5x-4x> 4x - 4x-20; 1x< -20; you have to get x by itself so you divide both side by 1; 1x/1 < -20/1; x< -20 that is how I got x<-20

- Algebra -
**bobpursley**, Thursday, February 5, 2009 at 2:13pm
I agree with your 5x-4x> 4x - 4x-20;

that simplifies to x>-20

From there, your work makes no sense, and is in fact wrong. Dividing by 1 does not reverse the inequality sign

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