Posted by Ellen on Thursday, February 5, 2009 at 12:12am.
let her time walking be t hours
then the distance she walked = 3t miles
let her time jogging back home be 1/4 - t hours
so the distance she jogged = 6(1/4 - t)
but aren't those two distances the same ?
so...
3t = 6(1/4 - t)
I am sure you can solve this for t, then sub that value back into 3t to get the distance.
Wait, I don't get it.
I solved
3t = 6 (1/4 - t)
and got 11.66666666666....
and then what do I do?
..or did I do that wrong?
3t = 6 (1/4 - t)
3t = 3/2 - 6t
9t = 3/2
t = 3/18 = 1/6
then 3t, which was the distance
= 3(1/6) = 1/2
so the distance is 1/2 mile
check:
time walking = 1/2 ÷ 3 = 1/6 hour
time jogging = 1/2 ÷ 6 = 1/12 hour
1/6 + 1/12 = 2/12 + 1/12 = 3/12 = 1/4 hour
Oh, i see.
thank you.
Related Questions
physics - Mary walked north from her home to Sheila's home, which is 4.0 ...
6th grade Math - What is the average (mean) distance you walked? Mon-1 2/3 mi. ...
physics - A car travels along a straight stretch of road. It proceeds for 11.9 ...
physics - A car travels along a straight stretch of road. It proceeds for 14 mi ...
physics - A car travels along a straight stretch of road. It proceeds for 15 mi ...
physics - A car travels along a straight stretch of road. It proceeds for 15 mi ...
physics - A car travels along a straight stretch of road. It proceeds for 14 mi ...
Navigation - A fisherman leaves his home port and heads in the direction N 70 ...
Algebra II - A salesman drove from his home to a nearby city at an average speed...
physics - A car travels along a straight stretch of road. It proceeds for 14 mi ...
For Further Reading