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September 16, 2014

September 16, 2014

Posted by **Bill** on Wednesday, February 4, 2009 at 9:30pm.

a ball is thrown with an initial velocity of 40 ft/second from a height of 4 feet. h(t)=-16t+40t+4

a) what is the highest point reached by the ball?

b) at what time will the ball reach the highest point?

- Algebra 2 -
**bobpursley**, Wednesday, February 4, 2009 at 9:48pmyour formula is wrong.

h(t)=-16t^2 + 40t+4

v(t)=40-16t

so max height is when v(t)=0 or t=40/16

and the max height is found by plugging that into the height equation.

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