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Posted by on Wednesday, February 4, 2009 at 9:30pm.

Okay I have :
a ball is thrown with an initial velocity of 40 ft/second from a height of 4 feet. h(t)=-16t+40t+4

a) what is the highest point reached by the ball?

b) at what time will the ball reach the highest point?

  • Algebra 2 - , Wednesday, February 4, 2009 at 9:48pm

    your formula is wrong.
    h(t)=-16t^2 + 40t+4

    so max height is when v(t)=0 or t=40/16
    and the max height is found by plugging that into the height equation.

  • Algebra 2 - , Saturday, January 28, 2017 at 11:14pm

    5 seconds

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