Saturday

April 19, 2014

April 19, 2014

Posted by **Bill** on Wednesday, February 4, 2009 at 9:30pm.

a ball is thrown with an initial velocity of 40 ft/second from a height of 4 feet. h(t)=-16t+40t+4

a) what is the highest point reached by the ball?

b) at what time will the ball reach the highest point?

- Algebra 2 -
**bobpursley**, Wednesday, February 4, 2009 at 9:48pmyour formula is wrong.

h(t)=-16t^2 + 40t+4

v(t)=40-16t

so max height is when v(t)=0 or t=40/16

and the max height is found by plugging that into the height equation.

**Related Questions**

Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

algebra - when a ball is thrown up into the air it makes the shape of a parabola...

Algebra - If a ball is thrown vertically upward from a height of 56ft. above ...

Algebra 2 - If an object is thrown vertically upward with an initial velocity of...

Algebra - If an object is thrown vertically upward with an initial velocity of ...

calculus - a ball is thrown directly upward with a velocity of 40 feet/seconds. ...

calculus - a ball is thrown directly upward with a velocity of 40 feet/seconds. ...

calculus - a ball is thrown directly upward with a velocity of 40 feet/seconds. ...

algebra - a ball is thrown downward from the too of 110 ft bldg with an initial ...