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March 30, 2017

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Q, What volume of 0.472 mol/L AgNO3 will precipitate the chloride ion in 40ml of 0.183 mol/L AlCl3?

- Answer is 46.6ml, but how to solve this question?

  • another 12 chem Q. (science) - ,

    Moles Ag= Volume*Molarity
    But moles of Ag has to equal moles of Cl ion (it forms AgCl).
    Moles Cl=.04*.184*3 (three ions in AlCl3)
    set them equal, and solve for Volume

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