Posted by kate on Wednesday, February 4, 2009 at 6:50am.
x^2+6x+5/x^2+8x+15
for what values is # underfined.

algebra help  Reiny, Wednesday, February 4, 2009 at 8:24am
I recall responding to a very similar, perhaps the same question yesterday.
Unless you clarify with brackets where the division starts and ends, I cannot be precise in my answer
the way it stands, only the x^2 is divided, so the expression is undefined for x=0
I am certain you meant:
(x^2+6x+5)/(x^2+8x+15) which then
= ((x+1)(x+5))/((x+3)(x+5))
= (x+1)/(x+3)
so the expression is undefined for x = 3, or x=5
Some would argue that the expression is undefined for x = 3, and indeterminate for x = 5.
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