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March 29, 2017

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x^2+6x+5/x^2+8x+15

for what values is # underfined.

  • algebra help - ,

    I recall responding to a very similar, perhaps the same question yesterday.

    Unless you clarify with brackets where the division starts and ends, I cannot be precise in my answer
    the way it stands, only the x^2 is divided, so the expression is undefined for x=0

    I am certain you meant:
    (x^2+6x+5)/(x^2+8x+15) which then
    = ((x+1)(x+5))/((x+3)(x+5))

    = (x+1)/(x+3)

    so the expression is undefined for x = -3, or x=-5

    Some would argue that the expression is undefined for x = -3, and indeterminate for x = -5.

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