Considering the tube wherein HCL (1 M) was added to ethyl 4-aminobenzoate.
a) what reaction would occur in the tube?
b) write a balance equation that supports your explanation above?
c) describe what would happen if u added NaOH (6 M) to the same tube?
please help!! thank you
Consider the following:
1. Isn't the amino group basic. Adding an acid will form the HCl (hydrochloride) salt?
2. ArNH2 + HCl ==> ArNH3Cl. (I omitted the benzoate part).
3. Wouldn't the NaOH cleave the ester, forming the aminioacid + ethyl alcohol?
Check me out on this.
a) In the tube where HCl (1 M) was added to ethyl 4-aminobenzoate, a neutralization reaction would occur. The HCl would react with the amino group (NH2) of ethyl 4-aminobenzoate, resulting in the formation of a salt and water.
b) The balanced equation for this reaction can be represented as follows:
C9H11NO2 + HCl → C9H11NO2HCl + H2O
c) If NaOH (6 M) is added to the same tube, it would result in another neutralization reaction. Sodium hydroxide (NaOH) is a strong base and would react with the remaining HCl and any unreacted ethyl 4-aminobenzoate. The reaction would result in the formation of water and the corresponding sodium salt.
The balanced equation for this reaction can be represented as follows:
C9H11NO2HCl + NaOH → C9H11NO2Na + H2O + NaCl