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Formic acid is only readily soluble in water and in both 0.6 M NaHCO3 and 2.5 M NaOH.
give a brief explanation of the reaction for each

  • Chemistry - ,

    Same answer as above for hexanoic acid.

  • Chemistry - ,

    These are typical reactions between and acid and a bicarbonate, and an acid and a base. Sodium formate (a salt) and H2O are forming in both cases. CO2 is forming typically when a base reacts with a bicarbonate or a carbonate.

    HCOOH + NaHCO3 ---> HCOONa + H2O + CO2

    HCOOH + NaOH ---> HCOONa + H2O

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