Considering the tube wherein HCL (1 M) was added to ethyl 4-aminobenzoate.
a) what reaction would occur in the tube?
b) write a balance equation that supports your explanation above?
c) describe what would happen if u added NaOH (6 M) to the same tube?
please help!! thank you
Sure, I can help you with that!
a) In the tube where HCl (hydrochloric acid, 1 M) is added to ethyl 4-aminobenzoate, a reaction called an acid-base reaction or a neutralization reaction would likely occur. The acid (HCl) reacts with the base (ethyl 4-aminobenzoate), leading to the formation of a salt and water.
b) To write a balanced chemical equation supporting the explanation above, we need to know the molecular formula of ethyl 4-aminobenzoate. Assuming its molecular formula is C9H11NO2, the balanced equation would be:
C9H11NO2 + HCl → C9H11NO2Cl + H2O
In this equation, the ethyl 4-aminobenzoate (C9H11NO2) reacts with hydrochloric acid (HCl) to form the salt ethyl 4-aminobenzoate hydrochloride (C9H11NO2Cl) and water (H2O).
c) If you were to add NaOH (sodium hydroxide, 6 M) to the same tube, it would lead to another acid-base reaction. Sodium hydroxide is a strong base, so it would react with the remaining acid (HCl or ethyl 4-aminobenzoate hydrochloride) present in the tube.
The reaction would be:
HCl + NaOH → NaCl + H2O
In this equation, hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water (H2O).