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February 27, 2015

February 27, 2015

Posted by **Anonymous** on Tuesday, February 3, 2009 at 9:44pm.

The coordinates of D are (-2h, 0) and G are (h,k).

Using the distance formula I got the distance of DG to be the square root of 3h squared + k squared.

Using the distance formula I got the distance of EH to be -3h squared + k squared.

I know the two distances should be equal. I don't know why the second segment is coming out with that negative 3. I must have made a mistake somewhere... please help.

- geometry -
**Reiny**, Tuesday, February 3, 2009 at 10:32pmYou did not state the coordinates of E and H.

- geometry -
**kyle**, Tuesday, February 3, 2009 at 10:45pmhow do i fid the surface are for this shape??? HELP!

- geometry -
**Anonymous**, Tuesday, February 3, 2009 at 10:59pmoops.

E (2h, 0)

A (0, 2k)

- geometry -
**Anonymous**, Tuesday, February 3, 2009 at 11:01pmoops again.

E (2h, 0)

H (-h, k)

- geometry -
**Reiny**, Tuesday, February 3, 2009 at 11:08pmEH = √(2h-(-h))^2 + (0-k)^2)

= √(9h^2 + k^2)

which is the same as your other length

- geometry -
**Anonymous**, Tuesday, February 3, 2009 at 11:20pmhow could it be 9h squared? If you squared the 3? shouldn't that.. square be gone? I don't understand...

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