Posted by **Karen** on Tuesday, February 3, 2009 at 8:19pm.

If the sum of two numbers is 1 and the sum of the cubes of the numbers is 3, what is the sum of the squares of the numbers?

- Pre-Calculus -
**bobpursley**, Tuesday, February 3, 2009 at 8:32pm
m+n=1

m^3+n^3=1

What if one number is zero, so the other number is ....

- Pre-Calculus -
**Karen**, Tuesday, February 3, 2009 at 8:41pm
No, the sum of the cubes is 3 so its m+n=1 m^3+n^3=3

- Pre-Calculus -
**bobpursley**, Tuesday, February 3, 2009 at 8:51pm
oooppppssss

m+n=1

m^3+n^3=3

If you factor the second equation..

(M+n)(M^2-mn+n^2) the first term is 1, so

(m^2+n^2 -mn)=3 equation1

but if we square the first equation given

m^2+2mn+n^2 = 1

m^2+n^2+2mn=1 equation2

subtracting equation2 from equation1

-mn-2mn=2

or -3mn=2

OK, this is not making sense. Check my work, I will try again later.

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