Posted by **april** on Tuesday, February 3, 2009 at 6:51pm.

A horizontal force of 200 N is applied to a 55 kg cart across a 10 m level surface. If the cart accelerates at 2 m/s^2 then what is the work done by the force of friction as it acts to retard the motion of the cart? Hint calculate the force of friction using newtons second law.

the answer is -900J...but how do i get that?

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