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Posted by on Tuesday, February 3, 2009 at 6:51pm.

A horizontal force of 200 N is applied to a 55 kg cart across a 10 m level surface. If the cart accelerates at 2 m/s^2 then what is the work done by the force of friction as it acts to retard the motion of the cart? Hint calculate the force of friction using newtons second law.

the answer is -900J...but how do i get that?

  • physics - , Tuesday, February 3, 2009 at 6:58pm

    There are a couple of ways to do this.

    Netforce= ma
    200N+friction=ma
    -200N + ma=friction solve for friction force.
    Work done on by friction=forcefricion(10m)
    Now notice

  • physics - , Tuesday, February 3, 2009 at 7:06pm

    thanks

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