Monday

September 1, 2014

September 1, 2014

Posted by **Vincent** on Tuesday, February 3, 2009 at 9:41am.

Passes through the point (4,6); horizontal axis.

I know it has to be y^2=4px. But I don't know what to do with (4,6). Please show step by step. Thanks.

- Algebra2/Trig -
**Damon**, Tuesday, February 3, 2009 at 9:55amHorizontal axis means of form:

(y-k)^2 = 4p(x-h)

if the vertex is at the origin (h,k) = (0,0)

y^2 = 4 p x

36 = 4 p (4)

p = (9/4)

so

y^2 = 9 x

- Algebra2/Trig -
**Vincent**, Tuesday, February 3, 2009 at 10:06amOh, I see. Solve for P first then substitute it in. I guess I forgot that concept. Thanks!

**Related Questions**

College Algebra - Find the standard form of the equation of the parabola with ...

College Algebra - Find the standard form of the equation of the parabola with ...

Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...

Analytic Goemetry - Find the equation of the parabola whose axis is horizontal, ...

Calculus - For the parabola y^2=4px, where p, the focal length, is a constant, ...

Math - Find an equation of the parabola with vertex at the origin that passes ...

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...

algebra - Suppose a parabola has a vertex (-4,7) and also passes through the ...

Calculus - Find expressions for the quadratic functions whose graphs are shown. ...

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...