Posted by **Amber Olander** on Tuesday, February 3, 2009 at 8:53am.

A local computer center charges non-members $5.00 per session to use the media center. If you pay a membership fee of $25, you pay only $3 per session. Write an equation that can help you decide whether to become a member then solve the equation and interpret the solution.

- Math -
**PsyDAG**, Tuesday, February 3, 2009 at 9:31am
You save $2 per session. How many sessions do you have to have to equal or exceed your membership fee?

I hope this helps. Thanks for asking.

- Math -
**Reiny**, Tuesday, February 3, 2009 at 9:31am
C1 = 5x (non-members)

C2 = 3x + 25 (members)

So by equating these two functions, we can find out for how many sessions (x) it would be better to become a member.

5x = 3x + 25

2x = 25

x = 12.5 (12 or 13, we can't have half a session)

check: for 13 sessions

C1 = 65

C2 = 64

So for 13 or more sessions it would be cheaper to become a member, for sessions less than 13 the "pay-as-you-go" plan would be cheaper.

BTW Amber, it is not a good idea to use your full name on a public webpage like this. Your first name or some nickname is sufficient.

## Answer This Question

## Related Questions

- Math - Members at a yoga school pay $8 per class plus a one-time $90 membership ...
- Math - The theater offers a yearly membership for which customers pay a fee of $...
- algebra, please help - the membership fee for oining a camp association is 45 a...
- math - A rock-climbing gym charges non-members $16.00 per day to sue the gym ...
- math - A local gym charges nonmembers $10 per hour to use the tennis courts. ...
- Algebra I - A local gym charges nonmembers $8 per day to use the voleyball ...
- math - MOVIE CLUB Members of a movie rental club pay $15 annual membership fee ...
- Math - A local gym charge nonmembers $ 19 per hour to use the tennis courts. ...
- algebra - please help me write algebraic equation/ solution if membership for ...
- math - Members of the Campus Roller Rink pay a yearly membership fee of $50 plus...

More Related Questions