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December 18, 2014

December 18, 2014

Posted by **Chris** on Monday, February 2, 2009 at 10:41pm.

Type A=37% B=12.5% AB=3.5% O=47%

a)What is the Probability that the blood of any two unrelated people in a Red Cross blood drive belong to the same group?

Is this correct?

P(Ba)=.37 P(Bb)=.125 P(Bab)=.035 P(Bo)=.47

P(Samegroup)=P(Ba)^2+P(Bb)^2+P(Bab)^2+P(Bo)^2= 0.37465 ?

b)What is the probability that the blood of any four unrelated people in an american red cross blood drive belong to each of the four groups?

- Probability -
**economyst**, Tuesday, February 3, 2009 at 12:31pma) correct

b) four unrelated people standing in a row. Probability that they are in this exact order: A, B, AB, O is .37*.125*.035*.47 = .0007608

Now then, the number of ways these four people can be re-arranged is 4*3*2*1 = 24.

So, Probability is 24*.0007608 = .01826

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