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April 18, 2015

April 18, 2015

Posted by **Cathy** on Monday, February 2, 2009 at 8:09pm.

My teacher said to calculate the time of flight to get how long the arrow traveled for to get to the deer, but I don't angle of the arrow (unless its 180 degrees).

Formula:t = (65 m/s * sin (180))/(9.81 m/s^2)

- Physics -
**bobpursley**, Monday, February 2, 2009 at 8:26pmIf you dont shoot the arrow at an angle,it will NOT hit the deer, but hit the ground.

The horizontal speed of the arrow is 65cosTheta

The vertical speed is 65sinTheta.

Horizontal distance= horizvelocity*time

or time= 51/65cosTheta

Now put that time here:

Hfinal=Hinitial+ Vi*t -1/2 g t^2

but Hfinal=Hinitial,so

0=65sintheta *t - 4.9t^2

Now put the expression for t you got above, and solve for theta (it is a little messy, and you get two solutions).

Then go back and solve for time.

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