Posted by **Cathy** on Monday, February 2, 2009 at 8:09pm.

Problem: A hunter shoots an arrow at a deer directly away from him. When the arrow leaves the bow, the deer is at a distance of 38 m. When the arrow strikes, the deer is at a distance of 51.00 m. The speed of the arrow is 65.00 m/s. What must have been the speed of the deer? How long did the arrow take to travel to the deer?

My teacher said to calculate the time of flight to get how long the arrow traveled for to get to the deer, but I don't angle of the arrow (unless its 180 degrees).

Formula:t = (65 m/s * sin (180))/(9.81 m/s^2)

- Physics -
**bobpursley**, Monday, February 2, 2009 at 8:26pm
If you don't shoot the arrow at an angle,it will NOT hit the deer, but hit the ground.

The horizontal speed of the arrow is 65cosTheta

The vertical speed is 65sinTheta.

Horizontal distance= horizvelocity*time

or time= 51/65cosTheta

Now put that time here:

Hfinal=Hinitial+ Vi*t -1/2 g t^2

but Hfinal=Hinitial,so

0=65sintheta *t - 4.9t^2

Now put the expression for t you got above, and solve for theta (it is a little messy, and you get two solutions).

Then go back and solve for time.

## Answer This Question

## Related Questions

- Physics - An arrow, starting from rest, leaves the bow with a speed of 28.8 m/s...
- Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...
- Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...
- physics - Three deer, A, B, and C, are grazing in a field. Deer B is located 61....
- physics - Three deer, A, B, and C, are grazing in a field. Deer B is located 63....
- physics - Three deer, A, B, and C, are grazing in a field. Deer B is located 61....
- physics - A 77 g arrow is fired from a bow whose string exerts an average force ...
- physics - An 81 g arrow is fired from a bow whose string exerts an average force...
- physics - An 85 g arrow is fired from a bow whose string exerts an average force...
- Physics - A 87 g arrow is fired from a bow whose string exerts an average force ...

More Related Questions