Posted by It's me :) on Monday, February 2, 2009 at 12:27am.
Your equation for the second part b) is not correct.
It said "there are 3 times as many homes available with the second floor plan than the first"
which translates into y = 3x
subbing that back into the first gives you
x + (3x) = 56
x = 14 and then y = 3(14) = 56
the way you had it:
x+3y=56 you have stated conflicting conditions on x and y, and the only solution would be if y=0 and x = 56.
(three times zero is still zero)
for d) in x+y=56, if x=0, then y=56
if y=0 then x=56
so the intercepts are (56,0) and (0,56)
your second equation only has one intercept, namely the origin (0,0)
Sure enough, they would intersect at (14,42)
Thank you so much for your help! That makes more sense. I am getting ready to have a test next week so I am trying to practice as much as I can with these word problems. I do much better if the problem is right there staring me in the face but if I have to turn it into a problem I get stuck.
a) The sales representative here tells you they also have two floor plans available, but they only have 38 homes available. Write an equation that illustrates the situation. Use x and y to denote floor plan #1 and floor plan #2 respectively. X + Y = 38
b) The representative tells you that floor plan #1 sells for $175,000 and floor plan #2 sells for $200,000. She also mentions that all the available houses combined are worth $7,200,000. Write an equation that illustrates this situation. Use the same variables you used in part a.
175,000x + 200,000y = 7,2000,000
c) Use elimination to determine how many houses with each floor plan are available. Explain how you arrived at your answer.
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