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July 23, 2014

Homework Help: Physics

Posted by Cathy on Sunday, February 1, 2009 at 11:07pm.

Problem: A Super Ball is thrown to the ground with an initial downward velocity of 0.70 m/s and pops back up to the hand of the thrower; the total time elapsed is 0.71 s. What height was the Super Ball thrown from?

Do I use the formula x = x0 + v0*t-0.5*g*t^2?

x0=0
v0=-0.70
t=0.71
g=9.81 m/s^2

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