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Algebra 2

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i'm not sure how to evaluate this

(6)/(X^-4) + (5)/(X^-2)

  • Algebra 2 -

    the common denominator would be
    (x^2-4(x^2-2), so

    (6)/(X^-4) + (5)/(X^-2)
    = [6(x^2-2) + 5(x^2-4)]/[(x^2-4(x^2-2)]
    = (11x^2 - 32)/[(x^2-4(x^2-2)]

    (are you sure the second denominator wasn't (x-2) ?
    it would have worked much better)

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