will someone please double check my answer to this problem. the answer i get is a fraction, but not sure how to type it on here.

4(4y+2)=2(1+6y)+8

16y+8=2+12y+8
16y+8=10+12y
-16 -16
8=-6+12y
+6 +6
14=12y
divide both by 12 and that leaves y=14/12 then reduce down to 7/6

is this correct?

12

i don't know how you are getting this answer. can you explain to me what i need to do please. thanks ive been out of school since 1995 and i never took algebra in high school so im having a tough time in college.

Your mistake here is when you go from

16y + 8 = 10 + 12y

to

8 = -6 + 12y.

You aren't subtracting the same thing from both sides; you're subtracting 16y from the left, but 16 from the right. Assuming you mean to subtract 16y, you should end up with

8 = 10 - 4y

Subtract 10 from each side:

-2 = -4y

Multiply each side by -1/4:
1/2 = y.

okay i worked through this problem but at the end, i need to multiply? I thought i divided both by 4?

To double-check your answer, let's go through the steps you took to solve the equation.

First, you distributed the multiplication on both sides of the equation correctly:

4(4y + 2) = 2(1 + 6y) + 8
16y + 8 = 2 + 12y + 8

Then, you combined like terms by adding or subtracting:

16y + 8 = 10 + 12y

Next, you simplified the equation by subtracting 12y from both sides:

16y + 8 - 12y = 10 + 12y - 12y
-16y + 8 = 10

Then, you subtracted 8 from both sides:

-16y + 8 - 8 = 10 - 8
-16y = 2

At this point, it seems that you made an error. When subtracting 2 from both sides of the equation, you should have gotten a negative value (-2):

-16y = 2
-2 = 16y

After dividing both sides by 16, you correctly obtained:

-2/16 = y

Now, to simplify the fraction. The numerator (-2) and denominator (16) both have the common factor of 2. Dividing both terms by 2, you get:

-1/8 = y

Therefore, the correct answer is y = -1/8.