Posted by **amy** on Sunday, February 1, 2009 at 5:36pm.

will someone please double check my answer to this problem. the answer i get is a fraction, but not sure how to type it on here.

4(4y+2)=2(1+6y)+8

16y+8=2+12y+8

16y+8=10+12y

-16 -16

8=-6+12y

+6 +6

14=12y

divide both by 12 and that leaves y=14/12 then reduce down to 7/6

is this correct?

- math 012 -
**Tee-Tee**, Sunday, February 1, 2009 at 5:46pm
12

- math 012 -
**amy**, Sunday, February 1, 2009 at 5:52pm
i don't know how you are getting this answer. can you explain to me what i need to do please. thanks ive been out of school since 1995 and i never took algebra in high school so im having a tough time in college.

- math 012 -
**Noether**, Sunday, February 1, 2009 at 7:40pm
Your mistake here is when you go from

16y + 8 = 10 + 12y

to

8 = -6 + 12y.

You aren't subtracting the same thing from both sides; you're subtracting 16y from the left, but 16 from the right. Assuming you mean to subtract 16y, you should end up with

8 = 10 - 4y

Subtract 10 from each side:

-2 = -4y

Multiply each side by -1/4:

1/2 = y.

- math 012 -
**amy**, Sunday, February 1, 2009 at 8:01pm
okay i worked through this problem but at the end, i need to multiply? I thought i divided both by 4?

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