Posted by bob on Saturday, January 31, 2009 at 4:01pm.
well, looking at the curves, The area will be (x2-x1) dy or (6-y - y^2 )dy ...check that.. with the limits from y=1 to ymax, or
ymax occurs when
x are the same, or
y^2=6-y
y^2+y-6=0
(y+3)(y-2)=0
so the first quadrant ymax is 2
check that.
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