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March 27, 2015

March 27, 2015

Posted by **bob** on Saturday, January 31, 2009 at 4:01pm.

on the left by the curve y = sqrt(x), on the right by the curve y = 6 - x,

and below by the curve y = 1.

- calculus -
**bobpursley**, Saturday, January 31, 2009 at 4:49pmwell, looking at the curves, The area will be (x2-x1) dy or (6-y - y^2 )dy ...check that.. with the limits from y=1 to ymax, or

ymax occurs when

x are the same, or

y^2=6-y

y^2+y-6=0

(y+3)(y-2)=0

so the first quadrant ymax is 2

check that.

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