Wednesday

July 23, 2014

July 23, 2014

Posted by **bob** on Saturday, January 31, 2009 at 4:01pm.

on the left by the curve y = sqrt(x), on the right by the curve y = 6 - x,

and below by the curve y = 1.

- calculus -
**bobpursley**, Saturday, January 31, 2009 at 4:49pmwell, looking at the curves, The area will be (x2-x1) dy or (6-y - y^2 )dy ...check that.. with the limits from y=1 to ymax, or

ymax occurs when

x are the same, or

y^2=6-y

y^2+y-6=0

(y+3)(y-2)=0

so the first quadrant ymax is 2

check that.

**Related Questions**

calculus - Find the volume of the solid generated by revolving the region about ...

calculus - A region is bounded in the second quadrant by the curve y = ln(1–x), ...

calculus - Which has more area, the region in the first quadrant enclosed by the...

Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...

calculus - Find the volume of the solid generated by revolving the region about ...

Calculus - Determine the volume of the solid abtained when the region bounded by...

Calculus - 3) Consider rectangles located as shown in the first quadrant and ...

Calculus - Find the volume of the solid generated by revolving the following ...

Calculus - I'm having trouble with the following problem: Find the volume of the...

calculus - find the area of the region bounded by the polar curve r=sqrt(6ln(...