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December 20, 2014

December 20, 2014

Posted by **amy** on Friday, January 30, 2009 at 11:53pm.

Thanks!

- math 012 -
**drwls**, Friday, January 30, 2009 at 11:56pmYou may post your questions here, preferably one at a time (per post). Please include you own work so we can see what areas are giving you trouble. We do not accept emailed questions; this helps keep our email addresses secure.

- math 012 -
**amy**, Saturday, January 31, 2009 at 12:12amok thanks!

-6(1x-3)-26=-8

-6(1x-3)-26=-8

-6x+18-26=-8

-6x+44=-8

-44 -44

-6x=36

-6 =-6

x=6

- math 012 -
**drwls**, Saturday, January 31, 2009 at 5:41amIt is conventional to just write x, instead of 1x, wheneve the coefficient of an algebraic variable is 1.

There is a mistake in what you did.

Let's take a look.

-6(x-3)-26 = -8

-6x +18 -26 = -8

(You got that far OK)

-6x - 8 = -8

-6x = 0

x = 0

- math 012 -
**amy**, Saturday, January 31, 2009 at 10:40amOne more thing with this problem if you can explain for me. how come in the forth step, it is -6x=0?

- math 012 -
**drwls**, Saturday, January 31, 2009 at 11:37amI added 8 to both sides of the equation, thus eliminating it.

- math 012 -
**kathy**, Saturday, July 2, 2011 at 3:45pmhow to solve this math problem x/3 - 8 = -2

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