Posted by y912f on Friday, January 30, 2009 at 11:41am.
a. Add the times requred for each of the two driving intervals, and add 24 minutes (0.4 hours) to that sum.
For each driving inteveral, use the reationship
time = distance)/(average speed
The sum will be the total driving and waiting time. Call it T.
b. Divide (280 + 210)km by T
That is how to do it. You do the numbers.
ok thanks
so is this what i do:
280+210[how much they traveled]=490
then add .4 hours = 490.4
then :
T=490.4[distance]/average speed so 81.5?
my answer comes out 6.01 hours
i think im still doing something wrong
the last post was by y912f not mysterychicken
You did not follow my instructions. You cannot add distance (km) to time (hours) in physics. It makes no sense.
The total time is
T = 280/88 + 0.4 + 210/75 = 6.38 hours
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