Posted by **y912f** on Friday, January 30, 2009 at 11:41am.

please show me how to solve this

1. A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. the bus stops for 24 min. then, it travels 210 km south with an average velocity of 75 km/h to the south

a. how long does the total trip last?

answer=6.4 h

b. what is the average velocity for the total trip?

answer=77 km/h to the South

thanks to whoever helps=]

- Physics -
**drwls**, Friday, January 30, 2009 at 11:51am
a. Add the times requred for each of the two driving intervals, and add 24 minutes (0.4 hours) to that sum.

For each driving inteveral, use the reationship

time = distance)/(average speed

The sum will be the total driving and waiting time. Call it T.

b. Divide (280 + 210)km by T

That is how to do it. You do the numbers.

- Physics -
**y912f**, Friday, January 30, 2009 at 11:56am
ok thanks

- Physics -
**mysterychicken**, Friday, January 30, 2009 at 12:03pm
so is this what i do:

280+210[how much they traveled]=490

then add .4 hours = 490.4

then :

T=490.4[distance]/average speed so 81.5?

my answer comes out 6.01 hours

i think im still doing something wrong

- Physics -
**y912f**, Friday, January 30, 2009 at 12:05pm
the last post was by y912f not mysterychicken

- Physics -
**drwls**, Friday, January 30, 2009 at 1:10pm
You did not follow my instructions. You cannot add distance (km) to time (hours) in physics. It makes no sense.

The total time is

T = 280/88 + 0.4 + 210/75 = 6.38 hours

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