# Physics

posted by on .

please show me how to solve this
1. A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. the bus stops for 24 min. then, it travels 210 km south with an average velocity of 75 km/h to the south
a. how long does the total trip last?
b. what is the average velocity for the total trip?

thanks to whoever helps=]

• Physics - ,

a. Add the times requred for each of the two driving intervals, and add 24 minutes (0.4 hours) to that sum.
For each driving inteveral, use the reationship
time = distance)/(average speed

The sum will be the total driving and waiting time. Call it T.

b. Divide (280 + 210)km by T

That is how to do it. You do the numbers.

• Physics - ,

ok thanks

• Physics - ,

so is this what i do:
280+210[how much they traveled]=490
then add .4 hours = 490.4
then :
T=490.4[distance]/average speed so 81.5?
my answer comes out 6.01 hours

i think im still doing something wrong

• Physics - ,

the last post was by y912f not mysterychicken

• Physics - ,

You did not follow my instructions. You cannot add distance (km) to time (hours) in physics. It makes no sense.

The total time is
T = 280/88 + 0.4 + 210/75 = 6.38 hours