A 5.0kg textbook is raised a distance of 30.0cm as a student prepares to leave for school. How much work did the student do on the book?

Work = Force x (Distance raised)

I need to know what equatios to use!

(A)How much work is done moving a 2.0Kg book to a shelf 2.00m high? (B) What is the change of potential energy of the book as a result? (C) How much kineetic energy will the book have as it hits the ground when it falls?

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to get the force (N) you must multiply 2.0kg*9.81m/s to get the Newtons (Force)then finish the problem

3. A 5.0kg textbook is raised a distance of 30.0cm as a student prepares to leave for school. How much work did the student do on the book?

1470

Don't forget to convert the 30 cm into meters. It isnt 1470J. It is 14.70J

To find the work done on the book, we can use the formula:

Work = Force × Distance × cos(θ)

In this case, the force is the weight of the textbook, which is equal to its mass multiplied by the acceleration due to gravity (9.8 m/s²):

Force = mass × acceleration due to gravity
Force = 5.0 kg × 9.8 m/s²

The distance is given as 30.0 cm, but we need to convert it to meters:

Distance = 30.0 cm × 0.01 m/cm

Now, let's calculate the work done:

Work = Force × Distance × cos(θ)
Work = (5.0 kg × 9.8 m/s²) × (30.0 cm × 0.01 m/cm) × cos(θ)

Since the textbook is being raised, the angle θ between the force and displacement is 0 degrees (cos(0) = 1). Therefore, the cosine of θ is 1.

Work = (5.0 kg × 9.8 m/s²) × (30.0 cm × 0.01 m/cm) × 1

Now we can calculate the work:

Work = (5.0 kg × 9.8 m/s²) × (30.0 cm × 0.01 m/cm)
Work = 5.0 kg × 9.8 m/s² × 0.30 m

Work = 14.7 J

Therefore, the student did 14.7 Joules of work on the textbook.

(A) See my previous answer

(B) It equals the work done raising the book
(C) Ditto