Posted by physics on .
A 5.0 kg bucket of water is raised form a well by a rope. If the upward acceleratiopn of the bucket is 3.0 m/s^2 find the force exerted by the rope on the bucket of water
what exactly do i do here?
3.0 m/s^2 upward? is this the Fn? I have no idea how to do this problem...
The net force acting on the bucket is
Fn = T - Mg = M a
T is the tension in the rope.
T = M (g + a) = 12.8 m/s^2 * 5.0 kg = ?
odd i never seen this formula before and we haven't goten to tension yet thank you
The formula I used is Newton's second law. You probably have heard about that. Tension is one of the two forces acting on the bucket. The other is the weight force, W = M a