Posted by Anonymous on Wednesday, January 28, 2009 at 3:49pm.
d/dx e^u = e^u du/dx
here u = x^-1
du/dx = -1 x^-2
so
d/dx e^(x^-1) = -x^-2 e^(x^-1)
= -(1/x^2)e^(1/x^2)
Try the others using that recipe:
d/dx e^u = e^u du/dx
WOW that actually helps a lot and less confusing to solve! Thanks so much!
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