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September 30, 2014

September 30, 2014

Posted by **Anonymous** on Wednesday, January 28, 2009 at 3:49pm.

f(x) = e^(x^(-1))

f'(x) = -1(e^(x^(-2))e^(x^(-1))

f'(x) = -e^(x^(-2))e^(x^(-1))

?????

and... f(x) = 3^x

f'(x) = 3^x

- Math - Derivatives -
**Damon**, Wednesday, January 28, 2009 at 4:22pmd/dx e^u = e^u du/dx

here u = x^-1

du/dx = -1 x^-2

so

d/dx e^(x^-1) = -x^-2 e^(x^-1)

= -(1/x^2)e^(1/x^2)

Try the others using that recipe:

d/dx e^u = e^u du/dx

- Math - Derivatives -
**Anonymous**, Wednesday, January 28, 2009 at 4:34pmWOW that actually helps a lot and less confusing to solve! Thanks so much!

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