Precalculus
posted by Mary .
Find the values of x in the interval 0<=x<360 that satisfy the equation x=arcsin squareroot of 2/2. Express your answer in degrees.
360 degrees  45=315 degrees.
Is this right?

x = arcsin (√2/2)
since √2/2 is positive and the sine of an angle is positive in the I and II quadrant
x = 45 degrees or 135 degrees.
sin 315 =  √2/2 
Not quite. The angles that satisfy that equation are 45 and 135 degrees. the sine of 315 degrees is sqrt2/2
The Sine function is positive in the first and second quadrants 
Thanks