Posted by Mary on Wednesday, January 28, 2009 at 11:13am.
Find the values of x in the interval 0<=x<360 that satisfy the equation x=arcsin squareroot of 2/2. Express your answer in degrees.
360 degrees  45=315 degrees.
Is this right?

Precalculus  Reiny, Wednesday, January 28, 2009 at 12:26pm
x = arcsin (√2/2)
since √2/2 is positive and the sine of an angle is positive in the I and II quadrant
x = 45 degrees or 135 degrees.
sin 315 =  √2/2

Precalculus  drwls, Wednesday, January 28, 2009 at 12:26pm
Not quite. The angles that satisfy that equation are 45 and 135 degrees. the sine of 315 degrees is sqrt2/2
The Sine function is positive in the first and second quadrants

Precalculus  Mary, Wednesday, January 28, 2009 at 2:11pm
Thanks
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