Posted by **Mary** on Wednesday, January 28, 2009 at 11:13am.

Find the values of x in the interval 0<=x<360 that satisfy the equation x=arcsin squareroot of 2/2. Express your answer in degrees.

360 degrees - 45=315 degrees.

Is this right?

- Pre-calculus -
**Reiny**, Wednesday, January 28, 2009 at 12:26pm
x = arcsin (√2/2)

since √2/2 is positive and the sine of an angle is positive in the I and II quadrant

x = 45 degrees or 135 degrees.

sin 315 = - √2/2

- Pre-calculus -
**drwls**, Wednesday, January 28, 2009 at 12:26pm
Not quite. The angles that satisfy that equation are 45 and 135 degrees. the sine of 315 degrees is -sqrt2/2

The Sine function is positive in the first and second quadrants

- Pre-calculus -
**Mary**, Wednesday, January 28, 2009 at 2:11pm
Thanks

## Answer this Question

## Related Questions

- math - how to define arc cosine(cosine x) for -360 deg<x< 360 deg?? a ...
- trig - find to the nearesr degree, all values of x between 0 degrees and 360 ...
- Precalc - Find the values of x between (or equal to) 0 and 360 degrees to ...
- Calculus - Determine the measure of A if 0 degrees is less or equal to angle A ...
- trig - what are the values of theta in the interval 0 degrees is lessthan or ...
- math - find the angle that is coterminal to 525 degrees and lies between 0 ...
- trig - find two values of theta, zero degrees is than or equal to theta which is...
- physics - converting radians to degrees - i know how to convert degrees to ...
- Pre calculus - Solve for all values between zero and 360 degrees. cos(theta-42 ...
- trig - Solve the equation 2 tan C - 3 = 3 tan C-4 algebraically for all values ...

More Related Questions