Posted by **Mary** on Wednesday, January 28, 2009 at 11:13am.

Find the values of x in the interval 0<=x<360 that satisfy the equation x=arcsin squareroot of 2/2. Express your answer in degrees.

360 degrees - 45=315 degrees.

Is this right?

- Pre-calculus -
**Reiny**, Wednesday, January 28, 2009 at 12:26pm
x = arcsin (√2/2)

since √2/2 is positive and the sine of an angle is positive in the I and II quadrant

x = 45 degrees or 135 degrees.

sin 315 = - √2/2

- Pre-calculus -
**drwls**, Wednesday, January 28, 2009 at 12:26pm
Not quite. The angles that satisfy that equation are 45 and 135 degrees. the sine of 315 degrees is -sqrt2/2

The Sine function is positive in the first and second quadrants

- Pre-calculus -
**Mary**, Wednesday, January 28, 2009 at 2:11pm
Thanks

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