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A bullet with a mass 0.05kg is speeding toward a block of mass 10kg. the bullet is initially moving with a velocity of 200m/s while the block is initially at rest....The bullet collides with the block, sticking inside, and knocks the block horizontally of the edge of a cliff. the cliff is 10m tall. how far from the cliff does the block (with bullet inside) land?

  • physics - ,

    Use conservation of linear momentum to get the speed of the block with the bullet inside. Call that speed Vx

    m*Vb = (M + m) Vx
    M - block mass
    m = bullet mass
    Vb = bullet speed
    Solve for Vx

    Use the H = 10 m height of the building to compute the time the block takes to fall. Call that time T.
    H = (g/2)T^2
    Solve for T

    The distance that the block lands away from the cliff if Vx * T

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