posted by maria on .
A bullet with a mass 0.05kg is speeding toward a block of mass 10kg. the bullet is initially moving with a velocity of 200m/s while the block is initially at rest....The bullet collides with the block, sticking inside, and knocks the block horizontally of the edge of a cliff. the cliff is 10m tall. how far from the cliff does the block (with bullet inside) land?
Use conservation of linear momentum to get the speed of the block with the bullet inside. Call that speed Vx
m*Vb = (M + m) Vx
M - block mass
m = bullet mass
Vb = bullet speed
Solve for Vx
Use the H = 10 m height of the building to compute the time the block takes to fall. Call that time T.
H = (g/2)T^2
Solve for T
The distance that the block lands away from the cliff if Vx * T