Algebra
posted by Junior on .
I need help solving this equation.
[SQRT(x + 3)]  [SQRT(x  2)] =1
I know I am supposed to square each side however my teacher tells me I ahve to foil the lefthand side of the equation. Cna someone please help me with this.
Thank you.

well, if you square both sides
you get (FOIL)
x+32sqrt(x2)sqrt(x+3) + x2=1
2x+2 2sqrt( x^2+x6)=1
or 2x+22=2sqrt(x^2+x6)
square both sides
4x^2=4(x^2+x6)
x=6 
Thank you.

Would I do the same thing with this equation?
[SQRT(x + 7)]  2[SQRT(x)] =2
Beacause I see what you have showed me BUt i am stll a little bit confused. Please if you have the time help me. Thank you. 
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