Posted by **Chopsticks** on Monday, January 26, 2009 at 12:14am.

2/the 6th root of 81

the answer gave an answer of "2 3rd root of 3/3"

sorry i didn't type the root signs, i dunno how.

can you show me how to work this?

- alg 2+urgent please. -
**Chopsticks**, Monday, January 26, 2009 at 12:14am
the book gave me that answer.

- alg 2+urgent please. -
**Reiny**, Monday, January 26, 2009 at 9:08am
2/the 6th root of 81

= 2/[(3^4)^(1/6)]

= 2/3^(2/3)

now multiply top and bottom by 3^(1/3)

which would give you 3^(3/3) or 3 in the bottom

= 2(3^(1/3))/3

= 2*cuberoot(3)/3, your answer.

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