Posted by **Chopsticks** on Monday, January 26, 2009 at 12:14am.

2/the 6th root of 81

the answer gave an answer of "2 3rd root of 3/3"

sorry i didnt type the root signs, i dunno how.

can you show me how to work this?

- alg 2+urgent please. -
**Chopsticks**, Monday, January 26, 2009 at 12:14am
the book gave me that answer.

- alg 2+urgent please. -
**Reiny**, Monday, January 26, 2009 at 9:08am
2/the 6th root of 81

= 2/[(3^4)^(1/6)]

= 2/3^(2/3)

now multiply top and bottom by 3^(1/3)

which would give you 3^(3/3) or 3 in the bottom

= 2(3^(1/3))/3

= 2*cuberoot(3)/3, your answer.

## Answer this Question

## Related Questions

- Pre-Calculus - Solve 0 = 3x^2 + 5x -1 by completing the square. Express your ...
- Algebra check? - Sorry the first post formatted weirdly. 1. 3i - 10 --------- 8i...
- Math simplifying mixed radicals - Please help me simplify these following mixed ...
- maths surds please help and explain - Simplify A.1/root a +2 b.root 18/25 c.root...
- Math help please *calculus* - ok im having a bit of a problem rationalizing ...
- Math simplifying mixed radicals - Please help me simplify these following mixed...
- algebra - 1.)correct 2.)wrong---> the first term is wrong 4(3a^2)^2 = 36a^4 3...
- Algebra - Simplify: 5(cube root of 16) + 2(cube root of 54) 5 times the cube ...
- Pre-Calculus - Solve. Express your answer as exact roots. (s+6)^2 = 3/4 Sq root...
- Calculus - A rectangle is bounded by the x axis and the semicircle = square root...

More Related Questions