Posted by **Sophia** on Sunday, January 25, 2009 at 9:40pm.

An airplane traveling 1001 m above the ocean at 125km/h is going to drop a box of supplies to shipwrecked victims below. What is the horizontal distance between the plane and the victims when the box is dropped?

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**Sophia**, Sunday, January 25, 2009 at 10:28pm
The time is 14.3s, btw..

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**drwls**, Monday, January 26, 2009 at 3:20am
The time T that it will take the box to fall 1001 m, neglectring air resistance, is given by the equation

(g/2)T^2 = 1001

T^2 = 2002/9.8 = 204.3 s^2

T = 14.3 s

The distance that the box moves forward while it falls is V*T.

You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters.

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**Alison**, Monday, November 16, 2009 at 6:15pm
Givens:

a=-9.81m/s^2

d=-1001m

vi=0m/s

d=vit+1/2at^2

-1001m=1/2-9.81m/s^2t^2

-1001m=-4.905m/s^2t^2

divide -1001m by -4.905m/s^2

204s^2=t^2

square root both sides

14.3s=t

125km/hr is 56m/s

56*14.3=

800.8m, that's the distance from the package dropped.

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**Alison**, Monday, November 16, 2009 at 6:19pm
Woops!

125km/hr is 34.7m/s

so 34.7*14.3 is 496.21m

- physics -
**Michael**, Thursday, October 20, 2016 at 1:22pm
7.8m/s

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