Posted by Sophia on .
An airplane traveling 1001 m above the ocean at 125km/h is going to drop a box of supplies to shipwrecked victims below. What is the horizontal distance between the plane and the victims when the box is dropped?

physics 
Sophia,
The time is 14.3s, btw..

physics 
drwls,
The time T that it will take the box to fall 1001 m, neglectring air resistance, is given by the equation
(g/2)T^2 = 1001
T^2 = 2002/9.8 = 204.3 s^2
T = 14.3 s
The distance that the box moves forward while it falls is V*T.
You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters. 
physics 
Alison,
Givens:
a=9.81m/s^2
d=1001m
vi=0m/s
d=vit+1/2at^2
1001m=1/29.81m/s^2t^2
1001m=4.905m/s^2t^2
divide 1001m by 4.905m/s^2
204s^2=t^2
square root both sides
14.3s=t
125km/hr is 56m/s
56*14.3=
800.8m, that's the distance from the package dropped. 
physics 
Alison,
Woops!
125km/hr is 34.7m/s
so 34.7*14.3 is 496.21m 
physics 
Michael,
7.8m/s