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physics

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An airplane traveling 1001 m above the ocean at 125km/h is going to drop a box of supplies to shipwrecked victims below. What is the horizontal distance between the plane and the victims when the box is dropped?

  • physics - ,

    The time is 14.3s, btw..

  • physics - ,

    The time T that it will take the box to fall 1001 m, neglectring air resistance, is given by the equation
    (g/2)T^2 = 1001
    T^2 = 2002/9.8 = 204.3 s^2
    T = 14.3 s
    The distance that the box moves forward while it falls is V*T.

    You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters.

  • physics - ,

    Givens:
    a=-9.81m/s^2
    d=-1001m
    vi=0m/s

    d=vit+1/2at^2

    -1001m=1/2-9.81m/s^2t^2
    -1001m=-4.905m/s^2t^2
    divide -1001m by -4.905m/s^2

    204s^2=t^2
    square root both sides

    14.3s=t

    125km/hr is 56m/s
    56*14.3=
    800.8m, that's the distance from the package dropped.

  • physics - ,

    Woops!
    125km/hr is 34.7m/s
    so 34.7*14.3 is 496.21m

  • physics - ,

    7.8m/s

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