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Posted by **Sophia** on Sunday, January 25, 2009 at 9:40pm.

- physics -
**Sophia**, Sunday, January 25, 2009 at 10:28pmThe time is 14.3s, btw..

- physics -
**drwls**, Monday, January 26, 2009 at 3:20amThe time T that it will take the box to fall 1001 m, neglectring air resistance, is given by the equation

(g/2)T^2 = 1001

T^2 = 2002/9.8 = 204.3 s^2

T = 14.3 s

The distance that the box moves forward while it falls is V*T.

You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters.

- physics -
**Alison**, Monday, November 16, 2009 at 6:15pmGivens:

a=-9.81m/s^2

d=-1001m

vi=0m/s

d=vit+1/2at^2

-1001m=1/2-9.81m/s^2t^2

-1001m=-4.905m/s^2t^2

divide -1001m by -4.905m/s^2

204s^2=t^2

square root both sides

14.3s=t

125km/hr is 56m/s

56*14.3=

800.8m, that's the distance from the package dropped.

- physics -
**Alison**, Monday, November 16, 2009 at 6:19pmWoops!

125km/hr is 34.7m/s

so 34.7*14.3 is 496.21m

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