posted by gabriella on .
2) How many moles of nitrogen monoxide will be produced when 80.0 grams of oxygen are used? What volume of ammonia is needed?
this iz the equation
4NH3 + 5O2 -> 6H2O + 4NO
the 1st part i got 4 mol NO and i don't no how to do the 2nd prt
ok, your equation seems to be balanced
so for every mole of O2 you get (4/5) moles of NO
80 grams O2 / 32 grams/mole = 2.5 moles O2
2.5 * 4/5 = 2 moles NO
So we also have 2 moles of NH3
If at standard pressure and temp, 22.4 liters/mole
I think maybe you used 16 for O2 but the 16 is just one atomic mass for O in grams The molecular mass is 32 grams/mole
when they say 80 grams of oxygen I think they mean of the gas O2, not the atom O
i forgot to make oxygen diatomic and thanks for the second part :)