chemistry
posted by confused .
Benzene has a heat of vaporization of 30.72kj/mol and a normal boiling point of 80.1 C . At what temperature does benzene boil when the external pressure is 445 ? This is how I am solving this problem, but when I enter the answer it says im wrong. Can someone help with the math. Thanks
ln(445/760)= (30720/8.314)*(1/80  1/T2)

Your problem is that you are entering T as degrees C. You MUST use Kelvin (and don't throw away the 0.1 either).

The final answer is suppose to be in C. So therefore, would I solve the problem in Kelvin then convert back to degrees?

Cid you mean, "The final answer is supposed to be in C?" Yes. Convert 80.1 C to Kelvin by adding 273.16, then convert back to C for the final answer.

yes i was meaning C. For some reason im still getting the wrong answer probably my math, im going to keep trying it...thanks for your help

I worked it out and came out with 62.9 degrees C but check my math.

3.50 x 10^6 Km how do you express this in scientific notation in expaneded form.

I got 51.5?